Find value of x in the given pair of equations-1-x-1-y - 4 1-x-1-y - 2

The two equations are 1/x+1/y = 4 nbsp; 1/x 1/y = 2 nbsp; On adding both the equations, we get 1/x+1/y+1/x 1/y nbsp;= 4 + 2 ⇒2/x = 6 nbsp; ⇒ nbs ...

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Byju's Answer

Standard VIII

Mathematics

Addition of Negative Numbers

Find value of...

Question

Find value of $x$ in the given pair of equations.

$\frac{1}{x} + \frac{1}{y} = 4$

$\frac{1}{x} - \frac{1}{y} = 2$

$\frac{1}{3}$

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$\frac{1}{6}$

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Solution

The correct option is A
$\frac{1}{3}$

The two equations are

$\frac{1}{x} + \frac{1}{y} = 4$

$\frac{1}{x} - \frac{1}{y} = 2$

On adding both the equations, we get

$\frac{1}{x} + \frac{1}{y} + \frac{1}{x} - \frac{1}{y} = 4 + 2$

$\Rightarrow \frac{2}{x} = 6$

$\Rightarrow x = \frac{1}{3}$

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Similar questions

Find value of $x$ in the given pair of equations.

$\frac{1}{x} + \frac{1}{y} = 4$

$\frac{1}{x} - \frac{1}{y} = 2$

Find value of x and y in the given pair of equation, where $x \neq 0 & y \neq 0$ .
$\frac{2}{x} + \frac{3}{y} = 13$
$\frac{5}{x} - \frac{4}{y} = - 2$

Q. Find the value of x, y in the pair of equation given below, where

x \neq 0 & y \neq 0

\frac{2}{x} + \frac{3}{y} = 13

\frac{5}{x} - \frac{4}{y} = - 2

Find the values of $x$ and $y$ that satisfy the below given pair of equations, where $x \neq 0 & y \neq 0$ .

$\frac{2}{x} + \frac{3}{y} = 13$

$\frac{5}{x} - \frac{4}{y} = - 2$

Q. Find the values of x and y in the below given pair of equation, where

x \neq 0 & y \neq 0

\frac{2}{x} + \frac{3}{y} = 13

\frac{5}{x} - \frac{4}{y} = - 2

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Find value of x in the given pair of equations. 1x+1y=4 1x−1y=2

The correct option is A 13 The two equations are 1x+1y=4 1x−1y=2 On adding both the equations, we get 1x+1y+1x−1y=4+2 ⇒2x=6 ⇒x=13

Find value of $x$ in the given pair of equations.

$\frac{1}{x} + \frac{1}{y} = 4$

$\frac{1}{x} - \frac{1}{y} = 2$

The correct option is A
$\frac{1}{3}$

The two equations are

$\frac{1}{x} + \frac{1}{y} = 4$

$\frac{1}{x} - \frac{1}{y} = 2$

On adding both the equations, we get

$\frac{1}{x} + \frac{1}{y} + \frac{1}{x} - \frac{1}{y} = 4 + 2$

$\Rightarrow \frac{2}{x} = 6$

$\Rightarrow x = \frac{1}{3}$