Question

Find value of $x$:

$x-(2x-\frac{3x-4}{7})=\frac{4x-27}{3}-3$.

Answer 1

Given,

$x-(2x-\frac{3x-4}{7})=\frac{4x-27}{3}-3$

$\Rightarrow x-2x+\frac{3x-4}{7}=\frac{4x-27}{3}-3$

$\Rightarrow \frac{3x-4}{7}-x=\frac{4x-27-9}{3}$

$\Rightarrow 3(3x-4-7x)=7(4x-36)$

$\Rightarrow 9x-12-21x=28x-252$

$\Rightarrow 40x=240$

$\Rightarrow x=\frac{240}{40}$

$\Rightarrow x=6$.