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Question

Find value(s) of x, if
(i)2451=2x46x
(ii) 2345=x32x5

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Solution

(i) Given: 2451=2x46x
2(1)5(4)=2x(x)6(4)
220=2x224
18=2x224
2x2=18+24
2x2=6
x2=62
x=±3
Hence, values of x are ±3.

(ii) Given: 2345=x32x5
2(5)4(3)=x(5)2x(3)
1012=5x6x
2=x
x=2
Hence, value of x is 2.

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