Question

Find values of a,b,c and d
$\left(\begin{array}{cc}2a+b& a-2b\\ 5c-d& 4c+3d\end{array}\right)=\left(\begin{array}{cc}4& -3\\ 11& 24\end{array}\right)$

Answer 1

$2a+b=4⟶\left(i\right)$

$a-2b=-3⟶\left(ii\right)$

$5c-d=11⟶\left(iii\right)$

$4c+3d=24⟶\left(iv\right)$

$2\times \left(i\right)+\left(ii\right)$

$5a=5$

$a=1$

$a-2b=-3$

$2b=4$

$b=2$

$3\times \left(iii\right)+\left(iv\right)$

$19c=57$

$c=3$

$5c-d=11$

$d=4$