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Byju's Answer
Standard XII
Physics
Unit Vectors
Find P⃗ . Q...
Question
Find
→
P
.
→
Q
where
→
P
=
2
^
i
+
^
j
+
^
k
and
→
Q
=
^
i
−
^
j
+
2
^
k
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Solution
→
P
.
→
Q
=
(
2
^
i
+
^
j
+
^
k
)
.
^
i
−
^
j
+
2
^
k
)
=
2
−
1
+
2
=
3
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0
Similar questions
Q.
If
→
P
=
^
i
+
2
^
k
and
→
Q
=
2
^
i
+
^
j
−
2
^
k
are two vectors, find the unit vector parallel to
→
P
×
→
Q
. Also find the vector perpendicular to
P
and
Q
of magnitude
6
units.
Q.
Find a vector
→
r
in the plane of
→
p
=
−
^
i
+
^
j
and
→
q
=
−
^
j
+
^
k
such that
→
r
is perpendicular to
→
p
and
→
r
.
→
q
=
−
2
.
Q.
If
→
P
=
2
^
i
+
3
^
j
−
^
k
and
→
Q
=
2
^
i
−
5
^
j
+
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^
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.Find (i)
→
P
+
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(iI)
3
→
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−
2
→
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Q.
Find the shortest distance between the lines
→
r
=
(
^
i
+
2
^
j
+
^
k
)
+
λ
(
^
i
−
^
j
+
^
k
)
and
→
r
=
2
^
i
−
^
j
−
^
k
+
μ
(
2
^
i
+
^
j
+
2
^
k
)
.
Q.
Find the shortest distance between the lines.
→
r
=
^
i
+
2
^
j
+
^
k
+
λ
(
^
i
−
^
j
+
^
k
)
→
r
=
2
^
i
−
^
j
−
^
k
+
μ
(
2
^
i
+
^
j
+
2
^
k
)
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