Find what length of canvas $2$ m in width in required to make a conical tent $20$ m in diameter and $42$ m in slant height allowing $10$ % for folds and the stitching. Also find the cost of the canvass at the rate of Rs. $80$ per meter.

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Solution

Diameter of conical tent $= 20$ m
Radius $= 10$ m
Slant height $= 42$ m
$∴ C S A = π r l + π r^{2} = π (l + r) r$
$= \frac{22}{7} \times 10 \times 42 + \frac{22}{7} \times 10 \times 10 = 1320 + \frac{2200}{7} = 1320 + 314.2 = 1634.2 m^{2}$
$10$ % that is allowed in stitching $= \frac{10}{100} \times 1634.2 = 163.42 m^{2}$
Total cloth needed $= 1634.2 + 163.42 = 1797.62 m^{2}$
width of canvas $= 2$ m
Length of Canvas $= \frac{a r e a}{w i d t h} = \frac{1797.62 m^{2}}{2} = 898.81 m^{2}$
Cost of canvas $= R s .80 / m \times 898.81 m = R s .71904 .8$

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Find what length of canvas 2 m in width in required to make a conical tent 20m in diameter and 42 m in slant height allowing 10% for folds and the stitching. Also find the cost of the canvass at the rate of Rs. 80 per meter.

Find what length of canvas $2$ m in width in required to make a conical tent $20$ m in diameter and $42$ m in slant height allowing $10$ % for folds and the stitching. Also find the cost of the canvass at the rate of Rs. $80$ per meter.