Question

Find what value of $k,-4$ is a zero of the polynomial $x^2-x-(2k+2)$?

Answer 1

Given polynomial-

$x^2-x-(2k+2)=0$

Since $-4$ is a zero of the given polynomial.

Therefore,

${(-4)}^2-(-4)-(2k+2)=0$

$16+4-2k-2=0$

$18-2k=0$

$k=\frac{18}{2}=9$