Given series is
x1.2+x22.3+x33.4+x44.5+......
Here, an=xnn.(n+1)
If there exists an N so that n≥N
If L<1, then the series converges
If L>1, then the series diverges
If L=1, then the Ratio Test is inconclusive
Where, L=limn→∞∣∣∣an+1an∣∣∣
On applying ratio test, we get
L=limn→∞∣∣
∣
∣
∣
∣∣xn+1(n+1)(n+2)xnn(n+1)∣∣
∣
∣
∣
∣∣
On simplifying this, we get
L=limn→∞∣∣∣nx(n+2)∣∣∣
Finally on applying limit, we have
L=limn→∞∣∣
∣
∣∣x(1+2n)∣∣
∣
∣∣
∴L=|x|
i.e. series converges for x≤1 and diverges for x>1