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Question

Find whether the following series is convergent or divergent:
1+x2+x25+x310+....+xnn2+1+...

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Solution

To find whether the following series is convergent or divergent
Given series is
1+x2+x25+x310+......+xnn2+1+....
an=xnn2+1
According to Ratio test
If there exists an N so that nN
If L<1, then the series converges
If L>1, then the series diverges
If L=1, then the Ratio test is inconclusive
where, L=limnan+1an

On applying ratio test, we get
L=limnan+1an
L=limn∣ ∣ ∣ ∣ ∣xn+1(n+1)2+1xnn2+1∣ ∣ ∣ ∣ ∣

L=limnx(n2+1)(n+1)2+1

L=limnx(n2+1)n2+2n+2

L=limn∣ ∣ ∣x(1+1n2)1+2n+2n2∣ ∣ ∣

On applying limit, we have

L=|x|

For convergence, L<1
i.e. |x|<1
i.e. 1x1

Therefore, given series converges for 1x1
And diverges for x>1

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