Question

Find which of the following are perfect cubes?
(i) $243$ (ii) $588$ (iii) $1331$ (iv) $24000$ (v) $1728$ (vi) $1938$

Answer 1

$243=7^3$

$588=7^2\times 2^2\times 3$

$1331={11}^3$

$24000=3\times 2^3\times {10}^3$

$1728=3^3\times 4^3\times (12{)}^3$

$1938=3\times 2\times 323$

$\therefore$ The numbers which are perfect cubesw are $\Rightarrow 243,1331,1728$