Question

Find which of the following numbers are divisible by $6$:​
(i)$324$

Answer 1

Given: $324$​

​We know that, for a number to be divisible by $2$, its unit place must be even.​

​The digit at the unit place of $324\text{is}4$, which is even.​
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Hence, $324$ is divisible by $2$.​
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We know that, for a number to be divisible by $3$, its sum of digits must be divisible by $3$.​

$\text{Sum of digits of}324=3+2+4=9$

Since, $9$ is divisible by $3$.​
​
Hence, $324$ is divisible by $3$.​

For a number to be divisible by $6$, it must be divisible by both $2$ and $3$.​

Since $324$ is divisible by both $2$ and $3$.​

Hence, $324$ is divisible by $6$.​

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