Find work done by gravity in moving the block from B to A

- m g h

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m g h

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{m g h}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $m g h$
Here work is done along the gravity so the energy here is positive.
The potential energy can be written as $(W_{g})_{B t o A} = m g h$

Suggest Corrections

Similar questions

Q. A ball is thrown vertically upwards, it reaches the height

h

and then returns to the initial position. Work done by gravity when ball moves upwards is

W_{1}

and

W_{2}

when ball moves in downward direction. Then

Q. A block of mass

m

is moving down with constant velocity along an inclined plane of inclination

θ

. What is the work done by an external force (applied parallel to the inclined plane) in pulling the block up the inclined plane through a height

^{'} h^{'}

with constant velocity?

Q. A body dropped from a height H reaches the ground with a speed of

1.2 \sqrt{g H}

. Then the work done by air-friction is ---

A body of mass m rises to a height h = R/5 from the earth's surface where R is earth's radius. If g is acceleration due to gravity , the increase in PE is

A body dropped from a height H reaches the ground with a speed of 1.2 $\sqrt{g H}$ .Calculate the work doneby air-friction.

Join BYJU'S Learning Program

Find work done by gravity in moving the block from B to A

The correct option is B mghHere work is done along the gravity so the energy here is positive. The potential energy can be written as (Wg)B to A=mgh

The correct option is B $m g h$
Here work is done along the gravity so the energy here is positive.
The potential energy can be written as $(W_{g})_{B t o A} = m g h$