Using theorem based on the nbsp;external division of chords, PA × PB = PC nbsp;× PD......(1) Also, PC nbsp;× PD = PE nbsp;× PF.......(2) [1 mark] From ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Quadratic Equations Geometry Based Problems

Find x.[2 mar...

Question

Find $x$ .
[2 marks]

Open in App

Solution

Using theorem based on the external division of chords,
PA × PB = PC × PD......(1)
Also, PC × PD = PE × PF.......(2)
[1 mark]

From (1) and (2),
PA × PB = PE × PF
6 × 10 = 4 × (4 + $x$ )
$x$ = 15
[1 mark]

Suggest Corrections

Similar questions

Find $x : 4 x + 10 = 20$ [2 MARKS]

Q. Find the zeroes of the polynomial

p (x) = (x - 2)^{2} - (x + 2)^{2}

(2 marks)

Q. If

x = 2 + \sqrt{3}, x y = 1,

then find

\frac{x}{2 - x} + \frac{y}{2 - y}

. [2 Marks]

Q. If

x = 2 - \sqrt{3},

find the value of

(x - \frac{1}{x})^{3}

[2 Marks]

Q. Find the continued product:

(x - 1) (x + 1) (x^{2} + 1) (x^{4} + 1)

[2 marks]

Join BYJU'S Learning Program

Find x. [2 marks]

Using theorem based on the external division of chords, PA × PB = PC × PD......(1) Also, PC × PD = PE × PF.......(2) [1 mark] From (1) and (2), PA × PB = PE × PF 6 × 10 = 4 × (4 + x) x = 15 [1 mark]

Find $x$ .
[2 marks]

Using theorem based on the external division of chords,
PA × PB = PC × PD......(1)
Also, PC × PD = PE × PF.......(2)
[1 mark]

From (1) and (2),
PA × PB = PE × PF
6 × 10 = 4 × (4 + $x$ )
$x$ = 15
[1 mark]