Find x and y 1 3 x - y - 1 3 x - y - 3 4 1 2 3 x - y - 1 2 3 x - y - - 1 8

1 3 x + y + 1 3 x y = 3 4 ⋯(1) 1 2 ( 3 x + y ) 1 2 ( 3 x y ) = 1 8 1 #160; ( 3 x + y ) 1 #160; ( 3 x y ) = 1 ...

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Find x and ...

Question

Find $x$ and $y$
$\frac{1}{3 x + y} + \frac{1}{3 x - y} = \frac{3}{4}$

$\frac{1}{2 (3 x + y)} - \frac{1}{2 (3 x - y)} = \frac{- 1}{8}$

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\frac{1}{3 x + y} + \frac{1}{3 x - y} = \frac{3}{4}

\frac{1}{2 (3 x + y)} - \frac{1}{2 (3 x - y)} = \frac{- 1}{8}

\frac{1}{(3 x + y)} + \frac{1}{(3 x - y)} = \frac{3}{4} \frac{1}{2 (3 x + y)} - \frac{1}{2 (3 x - y)} = \frac{- 1}{8}

\frac{1}{3 x + y} + \frac{1}{3 x - y} = \frac{3}{4} \frac{1}{2 (3 x + y)} - \frac{1}{2 (3 x - y)} = - \frac{1}{8}

(1) \frac{2}{x} - \frac{3}{y} = 15; \frac{8}{x} + \frac{5}{y} = 77 (2) \frac{10}{x + y} + \frac{2}{x - y} = 4; \frac{15}{x + y} - \frac{5}{x - y} = - 2 (3) \frac{27}{x - 2} + \frac{31}{y + 3} = 85; \frac{31}{x - 2} + \frac{27}{y + 3} = 89 (4) \frac{1}{3 x + y} + \frac{2}{3 x - y} = \frac{3}{4}; \frac{1}{2 (3 x + y)} - \frac{1}{2 (3 x - y)} = - \frac{1}{8}

y = \frac{1}{3} x + \frac{1}{5}

y

x = 9

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