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Question

Find x and y if [2xxy3y][32]=[169]

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Solution

(2xxy3y)(32)=(169)]

Multiplying the rows of the first matrix and the first column of the second matrix we get the following matrix as

(6x+2x3y+6y)=(169)

(8x9y)=(169)

8x=16

x=2

9y=9

y=1

sox=2,y=1

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