Find x and y intercepts of the given line:
If the line x−12=y−3a=z+13 lies in the plane bx+2y+3z–4=0, then
11C01 + 11C12 + 11C23+.............. 11C1011 =
Two numbers A and B are given by A=2×11 and B=2×3×5×13.
Represent A×B as a product of its primes.