Question

Find $x$ and $y$ intercepts of the given line:

$3x+y=4$

• A. $a=\frac{4}{3},b=-4$
• B. $a=\frac{3}{4},b=\frac{1}{4}$
• C. $a=\frac{4}{3},b=4$
• D. $a=\frac{3}{4},b=\frac{1}{4}$

Answer 1

Answer: (C)

$a=\frac{4}{3},b=4$

Given equation is $3x+y=4$ ........ $\left(i\right)$

Let's represent the given equation in two-intercept form i.e. in the form of $\frac{x}{a}+\frac{y}{b}=1$, where $a$ is $x-$intercept and $b$ is $y-$intercept.

$3x+y=4$

$⟹\frac{3x}{4}+\frac{y}{4}=1$

$⟹\frac{x}{\frac{4}{3}}+\frac{y}{4}=1$

$a=\frac{4}{3},b=4$

Hence, option C is correct.