Question

Find $x$

$\frac{2(x-1)}{5}\le \frac{3(2+x)}{7}$

Answer 1

$\frac{2(x-1)}{5}\le \frac{3(2+x)}{7}$

$=>\frac{2x-2}{5}\le \frac{6+3x}{7}$

$=>14x-14\le 30+15x$

$=>15x-14x\ge -14-30$

$=>x\ge -44$