Question

Find x
$\frac{3x}{4}-\frac{1}{4}\left(x-20\right)=\frac{x}{4}+32$

Answer 1

$\frac{3x}{4}-\frac{1}{4}(x-20)=\frac{x}{4}+32$

$\Rightarrow \frac{3x-(x-20)}{4}=\frac{x+128}{4}$

$\Rightarrow 3x-(x-20)=x+128$

$\Rightarrow 3x-x+20=x+128$

$\Rightarrow 2x-x=128-20$

$\Rightarrow 2x=108$

$\Rightarrow x=\frac{108}{2}$

$\Rightarrow x=54$

Hence, this is the answer.