Question

Find $x$ if $14x=(47{)}^2-(33{)}^2$

Answer 1

$14x=(47{)}^2-(33{)}^2$

we know $a^2-b^2=(a+b)(a-b)$

$14x=(47+33)(47-33)$

$14x=80\times 14=1120$

$x=\frac{1120}{14}=80$

$\therefore$ Value of x is 80.