Find x if $2^{3 x} = 8^{2 x + 1}$

Open in App

Solution

Consider the given equation.
$2^{3 x} = 8^{2 x + 1}$
$2^{3 x} = (2^{3})^{2 x + 1}$
$2^{3 x} = 2^{3 (2 x + 1)}$

On equating both power, we get
$3 x = 3 (2 x + 1)$
$3 x = 6 x + 3$
$- 3 x = 3$
$x = - 1$

Hence, this is the answer.

Suggest Corrections

Similar questions

Question 177(v)

Find x.
$2^{3 x} = 8^{2 x + 1}$

Question 177(v)

Find x.
$2^{3 x} = 8^{2 x + 1}$

x

23 x = 69

x

{(\frac{- 3}{2})}^{6} \times {(\frac{4}{9})}^{3} = {(\frac{1}{2})}^{3 x}

f (x) = \frac{1}{2} (3^{x} + 3^{- x}), g (x) = \frac{1}{2} (3^{x} - 3^{- x})

f (x) g (y) + f (y) g (x)

Join BYJU'S Learning Program