Find $x,$ if:
$4^{2 x} = \frac{1}{32}$

\frac{- 4}{5}

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\frac{- 5}{4}

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\frac{4}{5}

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None of these

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Solution

The correct option is B $\frac{- 5}{4}$
$4^{2 x} = (\frac{1}{32}) 2^{4 x} = 2^{- 5} ∴ 4 x = - 5 x = (\frac{- 5}{4})$

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