find $x$ if : 5 ( x - 1 ) + 2 ( x + 3 ) + 6 = 0

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Solution

$5 (x - 1) + 2 (x + 3) + 6 = 0$
$\Rightarrow 5 x - 5 + 2 x + 6 + 6 = 0$
$\Rightarrow 7 x + 7 = 0$
$\Rightarrow 7 x = - 7$
$∴ x = - 1$

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