Find x- if- 14- - 36- - x8

Given, 14! + 36! = x8 or, #160; 124 + 1240 = x8 or, #160; 13 + 130 = x or, x=1130 ...

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Applications (Word Problem)

Find x, if:...

Question

Find $x$ , if:
$\frac{1}{4!} + \frac{3}{6!} = \frac{x}{8}$

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Solution

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x

\frac{1}{4!} + \frac{3}{6!} = \frac{x}{8!}

x

\frac{x}{6!} + \frac{3}{6!} = \frac{4}{8!}

\frac{x}{6!} - \frac{3}{6!} = \frac{4}{8!}

4^{[l o g_{2} l o g_{3} (4 x + 1)]} - l o g_{3} (4 x + 1)^{6} + 8 = 0

l o g_{4} (x - 4)

\sqrt{x + 3 - 4 \sqrt{(x - 1)}} + \sqrt{x + 8 - 6 \sqrt{(x - 1)}} = 1, x \in [n, 2 n]

n

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