Find ′x′ if 32x35=27.
Find x, if
(i) (14)−4×(14)−8=(14)−4x (ii) (−12)−19÷(−12)8=(−12)−2x+1(iii) (32)−3÷(32)5=(32)2x+1 (iv)(25)−3×(25)15=(25)2+3x(v) (54)−x÷(54)−4=(54)5 (vi) (83)2x+1×(83)5=(83)x+2
Solve
3x2:32x = 27:1
Find the values of x in each of the following:
(i)25x÷2x=5√220
(ii)(23)4=(22)x
(iii)(35)x(53)2x=12527
(iv)5x−2×32x−3=135
(v)2x−7×5x−4=1250
(vi)(3√4)2x+12=132
(vii)52x+3=1
(viii) (13)√x=44−34−6
(ix)(√35)x+1=12527