Question

Find $x$, if :
$\frac{x}{6!}+\frac{3}{6!}=\frac{4}{8!}$

Answer 1

$\frac{x}{6!}+\frac{3}{6!}=\frac{4}{8!}$

$\frac{x+3}{6!}=\frac{4}{8\times 7\times 6!}$

$x+3=\frac{4}{56}$

$56x+168-4=0$

$56x=-164$

$x=\frac{-164}{56}$

$x=-2.9285$

Check

$\frac{-2.92+3}{6!}=\frac{4}{8!}$

$\frac{0.0714}{720}=\frac{4}{40320}$

$0.000099=0.000099$