Find x if -3x-1-3x-6-3x-1-3x-6-7

The correct option is A 5 √(3x+1)+√(3x 6)√(3x+1) √(3x 6)=7 √(3x+1)+√(3x 6)=7(√(3x+1) √(3x 6)) √(3x+1)+√(3x 6)=7√(3x+1) 7√(3x 6) 8√(3x 6)=6√( ...

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Byju's Answer

Standard VIII

Mathematics

Finding Square Root through Prime Factorisation

Find x if √...

Question

Find x if $\frac{\sqrt{3 x + 1} + \sqrt{3 x - 6}}{\sqrt{3 x + 1} - \sqrt{3 x - 6}} = 7$

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Solution

The correct option is A 5
$\frac{\sqrt{3 x + 1} + \sqrt{3 x - 6}}{\sqrt{3 x + 1} - \sqrt{3 x - 6}} = 7$

$\sqrt{3 x + 1} + \sqrt{3 x - 6} = 7 (\sqrt{3 x + 1} - \sqrt{3 x - 6})$

$\sqrt{3 x + 1} + \sqrt{3 x - 6} = 7 \sqrt{3 x + 1} - 7 \sqrt{3 x - 6}$

$8 \sqrt{3 x - 6} = 6 \sqrt{3 x + 1}$

$4 \sqrt{3 x - 6} = 3 \sqrt{3 x + 1}$

squaring on both sides,

$16 (3 x - 6) = 9 (3 x + 1)$

$48 x - 96 = 27 x + 9$

$x = \frac{105}{21} = 5$

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Similar questions

Q. Differentiate

3 x^{1 / 3} + \frac{6}{7} x^{7 / 6} + 3 x^{2 / 3} + C

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x

\frac{(3 x + 1)}{6} + \frac{(2 x - 3)}{7} = \frac{(x + 3)}{8} + \frac{(3 x - 1)}{14}

Q. Find x

\frac{(4 x + 1)}{3} + \frac{(2 x - 1)}{2} - \frac{(3 x - 7)}{5} = 6

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Solve :

$\frac{9 x - 7}{3 x + 5} = \frac{3 x - 4}{x + 6}$

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Find x if √3x+1+√3x−6√3x+1−√3x−6=7

The correct option is A 5√3x+1+√3x−6√3x+1−√3x−6=7√3x+1+√3x−6=7(√3x+1−√3x−6)√3x+1+√3x−6=7√3x+1−7√3x−68√3x−6=6√3x+14√3x−6=3√3x+1squaring on both sides,16(3x−6)=9(3x+1)48x−96=27x+9x=10521=5

Find x if $\frac{\sqrt{3 x + 1} + \sqrt{3 x - 6}}{\sqrt{3 x + 1} - \sqrt{3 x - 6}} = 7$