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Question

Find x, if log10(x+1)+log10(x1)=log1011+2log103

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Solution

we know that
log10an=nlog10a

log10ab=log10a+log10b

So log10(x+1)+log10(x1)=log1011+2log103

log10(x+1)(x1)=log10(1132)

so x21=99x2=100

x=10

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