1
Question
Find 'x' if:
log (x-1) + log (x+1) = log21.
Find 'x' if:
log (x-1) + log (x+1) = log21.
Open in App
Solution
Log 1 base 2 = 0
as 2^0=1.
Now, log(x-1) + log(x+1) =log(1 to the base2)
log(x-1) + log(x+1) = 0
log ( x ^ 2 -1) = 0
10^0 = x ^2 -1
1+1 = x ^2
x = √2
Note : log x simply means log x to base 10
as 2^0=1.
Now, log(x-1) + log(x+1) =log(1 to the base2)
log(x-1) + log(x+1) = 0
log ( x ^ 2 -1) = 0
10^0 = x ^2 -1
1+1 = x ^2
x = √2
Note : log x simply means log x to base 10
Suggest Corrections
3
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
