Question

Find x if the ratio of cis isomer to trans isomer is 1:x in [M(AB)b${}_2$c${}_2$].

Answer 1

There are two trans isomers and one cis isomers in $\left[M\right(AB\left)b_2{c}_2\right]$. Hence, th ratio of cis isomer to trans isomer is 1:2