Find x if
$x^{2} - 4 x + 6 = x^{2} + 6 x - 9$

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Solution

$x^{2} - 4 x + 6 = x^{2} + 6 x - 9$

$x^{2} - 4 x + 6 - x^{2} - 6 x + 9 = 0 - 10 x + 15 = 0 x = \frac{15}{10} = 1.5$

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Similar questions

3 x^{2} - 6 x

x^{2} - 4 x + 4

x^{2} + x - 6

\frac{x^{2} - x - 6}{x^{2} - 9} \times \frac{x^{2} + 4 x + 3}{x^{2} + 5 x + 6}

\frac{x^{2} - 6 x + 9}{5 - 4 x - x^{2}} ⩾ 0

Factorise:

(i) x² + 6x + 8; (ii) x² + 4x + 3; (iii) a² + 5a + 6; (iv) a² − 5a + 6; (v) a² − 3a − 40; (vi) x² − x − 72.

f (x) = \sqrt{x^{2} + 6 x + 9} - \sqrt{x^{2} - 6 x + 9}

f (\frac{456}{123}) - f (- \frac{456}{123})

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