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Byju's Answer
Standard XII
Chemistry
Gamma Decay
Find x in t...
Question
Find
x
in the following nuclear reaction.
12
M
g
24
+
2
H
e
4
→
14
S
i
x
+
0
n
1
A
17
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B
27
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C
37
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D
24
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Solution
The correct option is
B
27
From conservation of mass
24
+
4
=
x
+
1
x
=
28
−
1
=
27
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0
Similar questions
Q.
Energy released in the nuclear fusion reaction is :
1
H
2
+
1
H
3
→
2
He
4
+
0
n
1
Atomic mass of some species are given below.
1
H
2
=
2.014
,
1
H
3
=
3.016
2
He
4
=
4.003
,
0
n
1
=
1.009
amu
.
Q.
Find the value of
x
in the following nuclear reaction.
7
N
14
+
2
H
e
4
→
x
O
17
+
1
H
1
Q.
Calculate the energy released in the following reaction.
3
L
i
6
+
0
n
1
→
2
H
e
4
+
1
H
3
Given :
Mass of
3
L
i
6
nucleus
=
6.015126
a
m
u
Mass of
1
H
3
nucleus
=
3.016049
a
m
u
Mass of
2
H
e
4
nucleus
=
4.002604
a
m
u
Mass of
0
n
1
=
1.008665
a
m
u
Q.
Match the following reactions:
(
A
)
4
B
e
9
+
2
H
e
4
→
6
C
12
+
⋯
(
i
)
2
H
e
4
(
B
)
6
C
12
+
⋯
→
5
B
10
+
2
H
e
4
(
i
i
)
0
n
1
(
C
)
7
N
14
+
⋯
→
8
O
17
+
1
H
1
(
i
i
i
)
1
D
2
(
D
)
20
C
a
40
+
⋯
→
19
K
37
+
2
H
e
4
(
i
v
)
1
H
1
Q.
Calculate
Q
value of the following nuclear reaction.
13
A
l
27
+
2
H
e
4
⟶
14
S
i
30
+
1
H
1
+
Q
The exact mass of
13
A
l
27
is
26.9815
a
m
u
,
14
S
i
30
is
29.9738
a
m
u
,
2
H
e
4
is
4.0026
a
m
u
and
1
H
1
is
1.0078
a
m
u
.
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