Question

Find x in the following proportions:
(i) 16 : 18 = x : 96
(ii) x : 92 = 87 : 116

Answer 1

(i) 16 : 18 = x : 96
⇒ 16, 18, x, and 96 are in proportion.
⇒ Product of extremes = Product of means
⇒ $16\times 96=18\times x$
⇒ $x=\frac{16\times 96}{18}$ = $\frac{256}{3}$
(ii) x : 92 = 87 : 116
⇒ x, 92, 87, and 116 are in proportion.
⇒ Product of extremes = Product of means
⇒ $x\times 116=87\times 92$
⇒ $x=\frac{87\times 92}{116}$ = 69