Question

Find $x$ of : ${1296}^{\frac{-1}{4}}[{1296}^{\frac{2}{4}}-{1296}^{\frac{1}{4}}]={\left(\sqrt{625}\right)}^{\frac{-x}{2}}$

Answer 1

$\frac{1}{6}[36-6]=(25{)}^{\frac{-x}{2}}$

$5=(25{)}^{\frac{-x}{2}}$

$x=-1$