Find x so that -5x-1-55-57-A- 2B- 1C- 6D- 7

The correct option is B 1 ( 5)^x+1× ( 5)^5 = ( 5)^7 ( 5)^x+1+5=( 5)^7 {∵ a^m × a^n = a^m+n} ( 5)^x+6 = ( 5)^7 Since bases are equal, powers powers will also ...

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Standard VIII

Mathematics

Exponents with like Bases

Find x so tha...

Question

Find x so that $(- 5)^{x + 1} \times (- 5)^{5} = (- 5)^{7}$ .

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Solution

The correct option is D
1

$(- 5)^{x + 1} \times (- 5)^{5} = (- 5)^{7}$
$(- 5)^{x + 1 + 5} = (- 5)^{7} {∵ a^{m} \times a^{n} = a^{m + n}}$
$(- 5)^{x + 6} = (- 5)^{7}$
Since bases are equal, powers powers will also be equal.
$x + 6 = 7$
$x = 7 - 6 = 1$
$x = 1$

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Find x so that (−5)x+1×(−5)5=(−5)7.

The correct option is D 1 (−5)x+1×(−5)5=(−5)7 (−5)x+1+5=(−5)7 {∵am×an=am+n} (−5)x+6=(−5)7 Since bases are equal, powers powers will also be equal. x+6=7 x=7−6=1 x=1

Find x so that $(- 5)^{x + 1} \times (- 5)^{5} = (- 5)^{7}$ .

The correct option is D
1

$(- 5)^{x + 1} \times (- 5)^{5} = (- 5)^{7}$
$(- 5)^{x + 1 + 5} = (- 5)^{7} {∵ a^{m} \times a^{n} = a^{m + n}}$
$(- 5)^{x + 6} = (- 5)^{7}$
Since bases are equal, powers powers will also be equal.
$x + 6 = 7$
$x = 7 - 6 = 1$
$x = 1$