Choose the correct answer in the given question. ∫√x2−8x+7dx is equal to (a)12(x−4)√x2−8x+7+9log|x−4+√x2−8x+7|+C(b)12(x+4)√x2−8x+7+9log|x+4+√x2−8x+7|+C(c)12(x−4)√x2−8x+7−3√2log|x−4+√x2−8x+7|+C(d)12(x−4)√x2−8x+7−92log|x−4+√x2−8x+7|+C