Question

Find x such that:

(i) $\frac{-1}{5}=\frac{8}{x}$
(ii) $\frac{7}{-3}=\frac{x}{6}$
(iii) $\frac{3}{5}=\frac{x}{-25}$
(iv) $\frac{13}{6}=\frac{-65}{x}$
(v) $\frac{16}{x}=-4$
(vi) $\frac{-48}{x}=2$

Answer 1

(i)$\frac{-1}{5}=\frac{8}{x}$

=> −x =5×8
=> x= −40

(ii)$\frac{7}{-3}=\frac{x}{6}$
=> (−3)x=7×6

=> x=$\frac{(7\times 6)}{(-3)}$
=> x=−14


(iii) $\frac{3}{5}=\frac{x}{-25}$
=> 5x=3×(−25)

=> x=$\frac{\mathrm{3\times (-25)}}{5}$
=>x = (−15)

(iv)$\frac{13}{6}=\frac{-65}{x}$

=> 13x=6×(−65)

=> x=$\frac{\mathrm{6\times }(-65)}{13}$

=> x= 6×(−​5)

=> x = −​30

(v)$\frac{16}{x}=-4$
=> $\mathrm{x\; =}\frac{16}{(-4)}$
=> x= (−4)

vi)$\frac{-48}{x}=2$
=> $\frac{-48}{2}=\frac{x}{1}$
=>$2x=(-48)\times 1$
=>$x=\frac{-48}{2}$
x= (−24)