Find X, Y and Z in the given sequence of reaction:
$C u C l_{2} (a q .) N H_{4} O H - ---- \to H_{2} S [X] H N O_{3} - --- \to Δ [Y] K C N - -- \to excess [Z]$

X = K_{2} C r O_{4}, Y = K_{2} C r_{2} O_{7}, Z = A g_{2} C r O_{4}

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X = [C r (O H)_{4}]^{-}, Y = N a_{2} C r O_{4}, Z = P b C r O_{4}

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X = Z n C O_{3}, Y = Z n O, Z = C o Z n O_{2}

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X = C u S, Y = C u (N O_{3})_{2}, Z = K_{3} [C u (C N)_{4}]

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Solution

The correct option is D $X = C u S, Y = C u (N O_{3})_{2}, Z = K_{3} [C u (C N)_{4}]$
Reaction:
$C u C l_{2} (a q .) N H_{4} O H - ---- \to H_{2} S [C u_{2} S] H N O_{3} - --- \to Δ [C u (N O_{3})_{2}] K C N - -- \to excess K_{3} [C u (C N)_{4}]$
$X = C u S, Y = C u (N O_{3})_{2}, Z = K_{3} [C u (C N)_{4}]$

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