wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find x+y if [x3xy4y] [21] =[512].

Open in App
Solution

Given:
[x3xy4y][21]=[512]

[2x+3x2y+4y]=[512]

[5x6y]=[512]

x=1,y=2
x+y=3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Multiplication of Matrices
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon