In figure, x = z are corresponding angles y = 40o nbsp;are corresponding angles x + 40o nbsp;+ 270o = 360o (angles at a point) x + 310o = 360o x = 50o So z ...

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Standard VII

Mathematics

Linear Pair

Find x, y, p ...

Question

Find x, y, p and z.

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Solution

In figure,
$x = z$ are corresponding angles
y = 40^o are corresponding angles
x + 40^o + 270^o = 360^o (angles at a point)
x + 310^o = 360^o
x = 50^o
So z = x = 50^o
p + z = 180^o (linear pair)
p + 50^o = 180^o
p = 130^o
Therefore, x = 50^o, y = 40^o, z = 50^o and p = 130^o

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Find x, y, p and z.

In figure, x=z are corresponding angles y = 40o are corresponding angles x + 40o + 270o = 360o (angles at a point) x + 310o = 360o x = 50o So z = x = 50o p + z = 180o (linear pair) p + 50o = 180o p = 130o Therefore, x = 50o, y = 40o, z = 50o and p = 130o

In figure,
$x = z$ are corresponding angles
y = 40^o are corresponding angles
x + 40^o + 270^o = 360^o (angles at a point)
x + 310^o = 360^o
x = 50^o
So z = x = 50^o
p + z = 180^o (linear pair)
p + 50^o = 180^o
p = 130^o
Therefore, x = 50^o, y = 40^o, z = 50^o and p = 130^o