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Equivalence Class

Find:x

Question

Find :

x

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Solution

The given relationship is,

On comparing L.H.S. and R.H.S. of the above relationship, we obtain

Differentiating this relationship with respect to x, we obtain

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y = x^{x}

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\frac{1 - x}{1 + x} = x

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lim x \to 0 (| x |)^{x}

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16 : x = x : 121

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