Find $y$ if $x = 4$ when $y = x^{3}$

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Solution

$y = x^{3} y = 4^{3} y = 64$

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Similar questions

x^{3} + y^{3} - 12 x y + 64

x + y = 4

x^{3} + y^{3} - 12 x y + 64,

x + y = - 4.

If x+y=5 and xy=6, then find x³-y³(x>y) [4marks]

x^{3} + y^{3}

x + y = 4

x y = 5

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