Question

find zeros of polynomial $f\left(x\right)=-(x-1{)}^3(x+1{)}^2$.

Answer 1

$\begin{array}{c}f\left(x\right)=0\\ ⟹-{\left(x-1\right)}^3{\left(x+1\right)}^2=0\\ ⟹{\left(x-1\right)}^3=0or{\left(x+1\right)}^2=0\end{array}$

So,

$x-1=0$ or $x+1=0$

$x=1$ or $x=-1$