Question

Find zeros of the polynomial $f\left(x\right)=x^2+99x+127$

Answer 1

$x^2+99x+127=0x=\frac{-99\pm \sqrt{{\left(99\right)}^2-4\left(127\right)}}{2}x=\frac{-99\pm \sqrt{{\left(99\right)}^2-4\left(127\right)}}{2}x=\frac{-99\pm \sqrt{9293}}{2}x=\frac{-99+\sqrt{9293}}{2},\frac{-99-\sqrt{9293}}{2}$