findthe value of X in the following proportion
(A) 9:27:: X:81
(B) 160:X:: 80 : 4
(C) 32:X::X:50
(D) 5:3::X:3

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Solution

Dear student
$A) We know that Product of extremes = Product of means 9 : 27 : : x : 81 \Rightarrow 9 \times 81 = 27 \times x \Rightarrow \frac{9}{27} = \frac{x}{81} \Rightarrow x = \frac{9 \times 81}{27} \Rightarrow x = 27 B) We know that Product of extremes = Product of means 160 : x : : 80 : 4 \Rightarrow 160 \times 4 = x \times 80 \Rightarrow \frac{160}{x} = \frac{80}{4} \Rightarrow \frac{160}{x} = 20 \Rightarrow x = 8 Try others as a part of practise .$
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