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Question

Finkelstein reaction for the preparation of alkyl iodide is based upon the fact that


A

Sodium iodide is soluble in methanol, while sodium chloride is insoluble in methanol

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B

Sodium iodide is soluble in methanol, while NaCl and NaBr are insoluble in methanol

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C

Sodium iodide is insoluble in methanol, while NaCl and NaBr are soluble

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D

The three halogens differ considerably in their electronegativity

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Solution

The correct option is B

Sodium iodide is soluble in methanol, while NaCl and NaBr are insoluble in methanol


RX+NaISoluble in(CH3OH,Me2CO)acetone−−−RI+NaXInsoluble in(CH3OH.Me2CO)
(where X=Cl or Br)


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