Finkelstein reaction is

2 C H_{3} C H_{2} C l + A g_{2} O (d r y) \to C H_{3} C H_{2} O C H_{2} C H_{3} + 2 A g C l

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C H_{3} C H_{2} B r + N a I Dry Acetone - ------ \to C H_{3} C H_{2} I + N a B r

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2 C H_{3} C H_{2} B r + A g_{2} O + H_{2} O \to 2 C H_{3} C H_{2} O H + 2 A g B r

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C H_{3} C H_{3} C l + N a O C H_{3} \to C H_{3} C H_{2} O C H_{3} + N a C l

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Solution

The correct option is B $C H_{3} C H_{2} B r + N a I Dry Acetone - ------ \to C H_{3} C H_{2} I + N a B r$
The Finkelstein reaction is an organic reaction where an alkyl halide is converted into another alkyl halide by reacting with NaI. This reactions occurs in the presence of dry acetone because NaI is more soluble in dry acetone whereas NaCl and NaBr are precipitated out. Thus, increasing of concentration of $I^{-}$ ion in the solution which favour the reaction to proceed in forward direction. The mechanism for this reaction is a simple, single-step bimolecular nucleophilic substitution reaction $(S_{N} 2)$ which like all $S_{N} 2$ reactions occur with inversion of stereochemistry.
$C H_{3} C H_{2} B r + N a I Dry Acetone - ------ \to C H_{3} C H_{2} I + N a B r$

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