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Byju's Answer

Standard XII

Chemistry

Trend in Ionisation Enthalpy

First and sec...

Question

First and second ionization enthalpies (in kJ/mol) of few elements are given below:
Element $E I_{I}$ $E I_{I I}$
(i) 520 980
(ii) 900 1760
(iii) 1680 3380
(iv) 2080 3963
Which of the above elements will form halides with formula $M X_{2}$ ?

(i) and (ii)

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(i) and (iii)

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(ii) and (iii)

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(i) and (iv)

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Solution

The correct option is B (i) and (ii)
Solution:- (A) $(i)$ and $(i i)$
The element $i$ and $i i$ have low first ionization energy and high second ionization energy. Therefore, it can form a predominantly stable covalent halide of the formula $M X_{2}$

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Similar questions

Q. The ionization enthalpies,

(I E)_{1}

and the

(I E)_{2}

in kJ mol

^{- 1}

of a few elements designated by Roman numerals are shown below :

Element	$(I E)_{1}$	$(I E)_{2}$
A	2372	5251
B	520	7300
C	900	1760
D	1680	3380

Which of the above elements form a stable binary halide of the formula

M X_{2}

Q. The first

(Δ_{i} H_{1})

and the second

(Δ_{i} H_{2})

ionization enthalpies (in kJ mol

^{- 1}

) and the

(Δ_{e g} H)

electron gain enthalpy (in kJ mol

^{- 1}

) of a few elements are given below:

Elements	$Δ H_{1}$	$Δ H_{2}$	$Δ_{e g}$ H
I	520	7300	-60
II	419	3051	-48
III	1681	3374	-328
IV	1008	1846	-295
V	2372	5251	+48
VI	738	1451	-40

Which of the above elements is likely to be :
(a) the least reactive element,
(b) the most reactive metal,
(c) the most reactive non-metal,
(d) the least reactive non-metal,
(e) the metal which can form a stable binary halide of the formula MX

_{2}

(X=halogen) and
(f) the metal which can form a predominantly stable covalent halide of the formula MX (X=halogen)?

The first (Δ_iH1) and the second (Δ_iH) ionization enthalpies (in kJ mol^–1) and the (Δ_egH) electron gain enthalpy (in kJ mol^–1) of a few elements are given below:

Elements	Δ_iH	Δ_iH	Δ_egH
I	520	7300	–60
II	419	3051	–48
III	1681	3374	–328
IV	1008	1846	–295
V	2372	5251	+48
VI	738	1451	–40

Which of the above elements is likely to be :

(a) the least reactive element.

(b) the most reactive metal.

(d) the least reactive non-metal.

(e) the metal which can form a stable binary halide of the formula MX₂, (X=halogen).

(f) the metal which can form a predominantly stable covalent halide of the formula MX (X=halogen)?

Q. The first (

Δ H_{1}

) and second (

Δ H_{2}

) ionisation enthalpies (in

k J m o l^{- 1}

) and the electron gain enthalpy (

Δ_{e g} H

) (in

k J m o l^{- 1}

) of the elements I, II, III, IV and V are given below:

Element	$Δ_{1} H_{1}$	$Δ_{1} H_{2}$	$Δ_{e g} H$
I	520	7300	-60
II	419	3051	-48
II	1681	3374	-328
IV	1008	1846	-295
V	2372	5251	+48

The most reactive metal and the least reactive non-metal of these are respectively.

The first

Δ_{i} H_{1}

and second

Δ_{i} H_{2}

ionisation enthalpies in kJ mol

^{- 1}

and the

Δ_{e q} H

electron gain enthalpy in kJ mol

^{- 1}

of a few elements are given below :

	Elements	$Δ_{i} H_{1}$	$Δ_{i} H_{2}$	$Δ_{e g} H$
(A)	P	520	7300	-60
(B)	Q	419	3051	-48
(C)	R	1681	3374	-328
(D)	S	1008	1846	-295
(E)	T	2372	5251	+48
(F)	U	738	1451	-40

The least reactive element is :

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Element	$E I_{I}$	$E I_{I I}$
(i)	520	980
(ii)	900	1760
(iii)	1680	3380
(iv)	2080	3963

First and second ionization enthalpies (in kJ/mol) of few elements are given below:ElementEIIEIII(i)520980(ii)9001760(iii)16803380(iv)20803963Which of the above elements will form halides with formula MX2?

The correct option is B (i) and (ii)Solution:- (A) (i) and (ii) The element i and ii have low first ionization energy and high second ionization energy. Therefore, it can form a predominantly stable covalent halide of the formula MX2

First and second ionization enthalpies (in kJ/mol) of few elements are given below:
Element $E I_{I}$ $E I_{I I}$
(i) 520 980
(ii) 900 1760
(iii) 1680 3380
(iv) 2080 3963
Which of the above elements will form halides with formula $M X_{2}$ ?

The correct option is B (i) and (ii)
Solution:- (A) $(i)$ and $(i i)$
The element $i$ and $i i$ have low first ionization energy and high second ionization energy. Therefore, it can form a predominantly stable covalent halide of the formula $M X_{2}$