First shell energy of $H e^{+}$ ion is $- 54.4 e V$ , then energy of its second shell is :-

- 54.4

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- 13.6

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- 27.2

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+ 27.2

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Solution

The correct option is B $- 13.6$ eV
Energy for nth orbital of any hydrogen-like species is given by,

$E_{n} = E_{0} / n^{2}$

where n is the principle quantum number.

So $E_{2} = - 54.4 / 4 = - 13.6 e V$ .

So the correct option is B.

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Similar questions

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First shell energy of He+ ion is −54.4eV, then energy of its second shell is :-

The correct option is B −13.6 eVEnergy for nth orbital of any hydrogen-like species is given by, En=E0/n2 where n is the principle quantum number. So E2=−54.4/4=−13.6eV. So the correct option is B.

First shell energy of $H e^{+}$ ion is $- 54.4 e V$ , then energy of its second shell is :-

The correct option is B $- 13.6$ eV
Energy for nth orbital of any hydrogen-like species is given by,

$E_{n} = E_{0} / n^{2}$

where n is the principle quantum number.

So $E_{2} = - 54.4 / 4 = - 13.6 e V$ .

So the correct option is B.