Five bags of rice weigh $150 k g .$ How many such bags of rice will weigh $900 k g$ ?

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Solution

Given: $150 k g$ of rice in $5$ bags.
$1 k g$ of rice will be in $\frac{5}{150}$ bags.
so, $900 k g$ of rice will require $= \frac{5}{150} \times 900 = 5 \times 6 = 30$ bags.
Hence, $30$ bags of rice will weigh $900 k g .$

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Five bags of rice weigh 150 kg. How many such bags of rice will weigh 900 kg?

Given: 150 kg of rice in 5 bags.1 kg of rice will be in 5150 bags. so, 900 kg of rice will require =5150×900=5×6=30 bags. Hence, 30 bags of rice will weigh 900 kg.

Five bags of rice weigh $150 k g .$ How many such bags of rice will weigh $900 k g$ ?

Given: $150 k g$ of rice in $5$ bags.
$1 k g$ of rice will be in $\frac{5}{150}$ bags.
so, $900 k g$ of rice will require $= \frac{5}{150} \times 900 = 5 \times 6 = 30$ bags.
Hence, $30$ bags of rice will weigh $900 k g .$